SOLVED: Using the following thermochemical equations, calculate the standard enthalpy of combustion for one mole of liquid acetone (C2H6O). C2H6O (I) + 4 O2 (g) â†' 2 CO2 (g) + 3 H2O (
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SOLVED: Check Your Understanding: Use the following thermochemical equations to find the heat of formation of diamond: C(diamond) + O2(g) -> CO2(g) ΔH° = -39544 kJ 2 CO(g) + O2(g) -> 2
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Calculate the standard enthalpy of the reactions 2C (graphite) + 3 H2(g)→ C2H6(g) from the following Δ H^∘ value (i) C2 H6(g) + 72 O2 (g)→ 2 CO2(g) + 3 H2 O (
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Given, C(graphite + O2(g) → CO2(g); ΔrH^o = - 393.5 kJ mol^-1 H2(g) + 12O2(g) → H2O(l); ΔrH^o = - 285.8 kJ mol^-1 CO2(g) + 2H2O(l) → CH4(g) + 2O2(g); Δ^rH6o = +
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